2)/(3x-1)4y=28,则y=7BE=BC CE=BC CA/2;CF=CA AF=CA AB/2loga[(x2^2-ax2)/(x1^2-ax1)]>0
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2)/(3x-1)4y=28,则y=7BE=BCCE=BCCA/2;CF=CAAF=CAAB/2loga[(x2^2-ax2)/(x1^2-ax1)]>02)/(3x-1)4y=28,则y=7BE=B
2)/(3x-1)4y=28,则y=7BE=BC CE=BC CA/2;CF=CA AF=CA AB/2loga[(x2^2-ax2)/(x1^2-ax1)]>0
2)/(3x-1)4y=28,则y=7
BE=BC CE=BC CA/2;CF=CA AF=CA AB/2loga[(x2^2-ax2)/(x1^2-ax1)]>0
2)/(3x-1)4y=28,则y=7BE=BC CE=BC CA/2;CF=CA AF=CA AB/2loga[(x2^2-ax2)/(x1^2-ax1)]>0
2y-x=4√a⒉-√b⒉=√〔a-b〕相对y=(m-1)x2 (m-2)x-1相对2y-x=4
上面的那个 x和2中间什么符号?
集合A={y|y=x²-4x+3},B={y|y=-x²-2x},那么A∩B=1、集合A={y|y=x²-4x+3},B={y|y=-x²-2x},那么A∩B=2、集合A={y|y=x²-4x+7},B={y|y=-x²-4x+3},那么A∩B=
集合A={y|y=x²-4x+3},B={y|y=-x²-2x},那么A∩B=1、集合A={y|y=x²-4x+3},B={y|y=-x²-2x},那么A∩B=2、集合A={y|y=x²-4x+7},B={y|y=-x²-4x+3},那么A∩B=
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3y+7/(y-1)(y-2)=A/(y-1)+B/(y-2),则A=( )B=( )若x+1/x=3,则x²/x^4+x²+1=( )
已知6x^2-7xy-3y^2+14x+y+a=(2x-3y+b)(3x+y+1),则a=?,b=?
若集合A={(x,y)|4x+y=6},B={(x,y)|3x+2y=7},则集合A∩B=
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(1)(x+y)^2-(x+y)^3(2)(x-y)-(x-y)^3(3)(x-y)^2-(y-x)^3(4)2(x-y)-3(y-x)^2(5)4ab(a=b)^2-6a^2b(a+b)(6)(x+y)^2(x-y)+(x+y)(x-y)^2(7)2a(a-3)^2-6a^2(3-a)+8a(a-3)(8)24xy^2z^2(x+y-z)-32xyz(z-x-y)^2+8xy(z-x-y)(9)(a-b)(b-a)^n(b-a)^2n-1 [两解)(10)2^2=3,2^b
几道 数学题急啊 对了再加20分(x+y)^2-(x+y)^3(x-y)^2-(x-y)^3 (x-y)^2-(y-x)^32(x-y)-3(y-x)^24ab(a+b)^2-6a^2b(a+b)(x+y)(x-y)-(x+y)^28a(x-y)^2-4b(y-x)a=-5 a+b+c=-5.2求代数式a^2(-b-c)-3.2a(c+b)的值
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集合A={(x,y)|x-2y=1}B={(x,y)|x+3y=6},则A∩B= A∪B=?