我急用.(不会的别答)全都要有过程...1.(lg根号27+lg8-3lg根号10)/lg1.2=_______2.4lg2+3lg5-lg1/5=__________3.(1+0.5lg9-lg240)/(1-2/3 lg27+lg36/5)=__________4.已知函数f(x)=loga【a在下面】(x+1),g(x)=loga{a在下面}(1-x)(a>0
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我急用.(不会的别答)全都要有过程...1.(lg根号27+lg8-3lg根号10)/lg1.2=_______2.4lg2+3lg5-lg1/5=__________3.(1+0.5lg9-lg240)/(1-2/3 lg27+lg36/5)=__________4.已知函数f(x)=loga【a在下面】(x+1),g(x)=loga{a在下面}(1-x)(a>0
我急用.(不会的别答)全都要有过程...
1.(lg根号27+lg8-3lg根号10)/lg1.2=_______
2.4lg2+3lg5-lg1/5=__________
3.(1+0.5lg9-lg240)/(1-2/3 lg27+lg36/5)=__________
4.已知函数f(x)=loga【a在下面】(x+1),g(x)=loga{a在下面}(1-x)(a>0且a不等于1)
(1)求f(x)+g(x)的定义域.
(2)判断f(x)+g(x)奇偶数,说明理由.
5.f(x)=log0.5【0.5在log下面】x,当x属于[a,a²],函数最大值比最小值大3,则a=________
6.已知2lg(x-2y)=lgx+lgy,则x/y的值是_______
我急用.(不会的别答)全都要有过程...1.(lg根号27+lg8-3lg根号10)/lg1.2=_______2.4lg2+3lg5-lg1/5=__________3.(1+0.5lg9-lg240)/(1-2/3 lg27+lg36/5)=__________4.已知函数f(x)=loga【a在下面】(x+1),g(x)=loga{a在下面}(1-x)(a>0
1.(lg根号27+lg8-3lg根号10)/lg1.2
=(3/2lg3+3lg2-3/2)/(lg12-1)
=(3/2)(lg3+2lg2-1)/(lg3+2lg2-1)
=3/2
2.4lg2+3lg5-lg1/5
=lg2^4+lg5^3+lg5
=lg(2^4*5^4)
=lg10^4=4
3.(1+0.5lg9-lg240)/(1-2/3 lg27+lg36/5)
=(lg10+lg3-lg240)/(lg10-lg9+lg36/5)
=lg(1/8) / lg8
=-1
4.(1)x+1>0 1-x>0
所以定义域为-10 y>0
所以x=y舍去,得x=4y
所以x/y=4
先给两题,等下再给....
1. 答案为:3/2;原式=(3lg3/2+3lg2-3lg10/2)/(lg12-lg10)
=[(3/2)(lg3-2lg2-1)]/(lg3+2lg2-1)=3/2
2. 答案为:4;原式=4lg2+3lg5-lg1+lg5=4(lg2+lg5)=4lg10=4
1)
(lg根号27+lg8-3lg根号10)/lg1.2
=(3/2lg3+3lg2-3/2)/(lg12-1)
=(3/2)(lg3+2lg2-1)/(lg3+2lg2-1)
=3/2
2)
4lg2+3lg5-lg1/5=4lg2+3lg5+lg5=4(lg2+lg5)=4lg10=4
3)
(1+0.5lg9-lg240)/(...
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1)
(lg根号27+lg8-3lg根号10)/lg1.2
=(3/2lg3+3lg2-3/2)/(lg12-1)
=(3/2)(lg3+2lg2-1)/(lg3+2lg2-1)
=3/2
2)
4lg2+3lg5-lg1/5=4lg2+3lg5+lg5=4(lg2+lg5)=4lg10=4
3)
(1+0.5lg9-lg240)/(1-2/3 lg27+lg36/5)
=(1+lg3-(1+3lg2+lg3))/(1-2lg3+(3lg2+2lg3-1))
=(-3lg2)/(3lg2)=-1
4)
(1)
x+1>0
1-x>0
得-1
f(x)+g(x)=loga{a在下面}(1+x)/(1-x)
f(-x)+g(-x)=loga{a在下面}(1-x)/(1+x)
=-loga{a在下面}(1+x)/(1-x)=-(f(x)+g(x))
5)
|log0.5【0.5在log下面】a^2-log0.5【0.5在log下面】a|=3
|log0.5【0.5在log下面】a|=3
a=8或1/8
6)2lg(x-2y)=lgx+lgy
(x-2y)^2=xy
x^2-5xy+y^2=0
x=y或x=4y
x-2y>0,x>0,y>0 舍去x=y
x/y=4
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1. (lg27½+lg8-3lg10½)/(lg12-lg10)
=(3lg3/2+3lg2-3/2)/(lg2²+lg3-1)
=3/2*(lg3+2lg2-1)/(lg2²+lg3-1)
=3/2
2. 4lg2+3lg5-lg1/5=4lg2+3lg5+lg5
=4lg2+4lg5
=4*(lg...
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1. (lg27½+lg8-3lg10½)/(lg12-lg10)
=(3lg3/2+3lg2-3/2)/(lg2²+lg3-1)
=3/2*(lg3+2lg2-1)/(lg2²+lg3-1)
=3/2
2. 4lg2+3lg5-lg1/5=4lg2+3lg5+lg5
=4lg2+4lg5
=4*(lg2+lg5)
=4
3. (1+0.5lg9-lg240)/(1-2/3 lg27+lg36/5)
=(1+lg3-lg24-lg10)/(1-2lg3+2lg6-lg5)
=(lg3-3lg2-lg3)/(lg2+lg5-2lg3+2lg2+2lg3-lg5)
=-3lg2/3lg2
=-1
4. (1)令F(x)=f(x)+g(x)=㏒a(x+1)+㏒a(1-x)
=㏒a(1-x²)
故下列等式同时成立:
x+1>0且1-x>0且1-x²>0
解得-1
(2)由(1)知F(x)关于原点对称,
且F(-x)=㏒a(1-x²)=F(x),故F(x)为偶函数。
5. a=8
∵f(x)为减函数,∴f(a)-f(a²)=3,即 ㏒0.5a-㏒0.5a²=3
解得a=8
6. ∵2lg(x-2y)=lgx+lgy,∴(x-2y)²=xy,
∴x²-4xy+4y²=xy即x²-5xy+4y²=0
方程两边同时除以y²得:(令Z=x/y)Z²-5Z+4=0,解得Z=1或4
经检验,x/y=1或4
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