已知1/a+1/b=3,则(a-5ab+b)/(4a+4b-3ab)=

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已知1/a+1/b=3,则(a-5ab+b)/(4a+4b-3ab)=已知1/a+1/b=3,则(a-5ab+b)/(4a+4b-3ab)=已知1/a+1/b=3,则(a-5ab+b)/(4a+4b-

已知1/a+1/b=3,则(a-5ab+b)/(4a+4b-3ab)=
已知1/a+1/b=3,则(a-5ab+b)/(4a+4b-3ab)=

已知1/a+1/b=3,则(a-5ab+b)/(4a+4b-3ab)=
1/a+1/b=3
即a+b=3ab
代入有
(a-5ab+b)/(4a+4b-3ab)
=(-2ab)/(9ab)
=-2/9

1/a+1/b=3,左边通分得:a+b/ab=3, a=3ab-b
代入右边,整理后得:-2ab/9ab=-2/9