化简根号下[1-cos(a-pi)]\2-3pi

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化简根号下[1-cos(a-pi)]\2-3pi化简根号下[1-cos(a-pi)]\2-3pi化简根号下[1-cos(a-pi)]\2-3pi应该是求根号下{[1-cos(a-pi)]\2}吧?[1

化简根号下[1-cos(a-pi)]\2-3pi
化简根号下[1-cos(a-pi)]\2
-3pi

化简根号下[1-cos(a-pi)]\2-3pi
应该是求根号下{[1-cos(a-pi)]\2}吧?
[1-cos(a-pi)]\2
=[1-cos(pi-a)]/2
=[1+cosa]/2
=[1+2(cos(a/2))^2-1]/2
=(cos(a/2))^2
而 -3pi/2