（x+y)(x+y-1)-12因式分解

来源：学生作业帮助网编辑：六六作业网时间：2024/07/10 14:10:05

（x+y)(x+y-1)-12因式分解（x+y)(x+y-1)-12因式分解（x+y)(x+y-1)-12因式分解(x+y)(x+y-1)-12=(x+y)[(x+y)-1]-12=(x+y)

（x+y)(x+y-1)-12因式分解
（x+y)(x+y-1)-12因式分解

（x+y)(x+y-1)-12因式分解
(x+y)(x+y-1)-12
=(x+y)[(x+y)-1]-12
=(x+y)²-(x+y)-12
=[(x+y)+3][(x+y)-4]
=(x+y+3)(x+y-4)
很高兴为您解答,【学习宝典】团队为您答题.
请点击下面的【选为满意回答】按钮.

（x+y)(x+y-1)-12因式分解因式分解：（1+x+y)(1-x-y) 因式分解:(x+y)-4(x+y-1) x^12-y^12因式分解因式分解xy-x-y+1 xy+x+y+1因式分解 1-x-y+xy 因式分解因式分解:xy+x+y+1 xy-1+x-y因式分解 xy-x-y+1因式分解因式分解12y(x-y)²-8(x-y)³ 把4（x-y+1)+y(y-2x)因式分解（x+y)*（x+1)-(xy+y*y)因式分解为多少因式分解:(x+y)(x-y)+4(y-1) y(y+2)+4x(x-y-1)因式分解是多少 (x+y)^2因式分解因式分解x²y-4y因式分解因式分解 x2(x+1)-y(xy+x)