1.(x-8y)(x-y+3)2.3.如图,△ABC中,D为AB中点,E在AC上,且BE垂直AC,若DE=10,AE=16,则BE的长度为()【求完整解题过程】急用,
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/15 06:10:37
1.(x-8y)(x-y+3)2.3.如图,△ABC中,D为AB中点,E在AC上,且BE垂直AC,若DE=10,AE=16,则BE的长度为()【求完整解题过程】急用,1.(x-8y)(x-y+3)2.
1.(x-8y)(x-y+3)2.3.如图,△ABC中,D为AB中点,E在AC上,且BE垂直AC,若DE=10,AE=16,则BE的长度为()【求完整解题过程】急用,
1.(x-8y)(x-y+3)
2.
3.如图,△ABC中,D为AB中点,E在AC上,且BE垂直AC,若DE=10,AE=16,则BE的长度为()
【求完整解题过程】急用,
1.(x-8y)(x-y+3)2.3.如图,△ABC中,D为AB中点,E在AC上,且BE垂直AC,若DE=10,AE=16,则BE的长度为()【求完整解题过程】急用,
1.(-1/9)^200×3^400=(-1/9)^200×9^200=(-1/9×9)^200=1
3.由于BE垂直AC,AD=BD,所以三角形ABE可以看作是以D为圆心DE为半径的圆的内接三角形,所以AD=BD=DE=10,则AB=20.在RT三角形ABE中,已知AB=20,AE=16,利用勾股定理,得BE=12
因式分解:a(x-y)^2+b(y-x)^3 4(x-y)^2+8(y-x)(x+y)1.a(x-y)^2+b(y-x)^3 2.4(x-y)^2+8(y-x)(x+y)
(x+y)(x-y)-(x-y)^2如题 (x+y)(x-y)-(x-y)^2
1.((y+2x)(-2x+y)+4(x+2y)^2)/3y 2.(2(x-y)^3-8(x-y)^2(x+y)+6y(x-y)^2)/2(x-y)^2
(2x+y)²+(x+3y)(x-3y)-x(5x+8y)因式分解
计算[x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y如题
[2(x-y)^5-8(x-y)^2(x+y)+6y(x-y)^2]÷2(x-y)^2[2(x-y)^3-8(x-y)^2(x+y)+6y(x-y)^2]÷2(x-y)^2
(3x-y)(3y+x)-(x-y)(x+y)
求二元一次方程练习题!如x-y=33x-8y=14x=y+3要习题。
【2(x-y)^3-8(x-y)^2(x+y)+6y(x-y)^2】/2(x-y)^2=
(x-8y)(x+y)
1.(x+2)^2-(x+y)^32.(x-y)^2-(x-y)^33.(x-y)^2-(y-x)^3
【2(x-y)(x-y)(x-y)-8(x-y)(x-y)(x+y)+6y(x-y)(x-y)]/2(x-y)(x-y)
如题{(X,Y)|(X+2)²+|Y-3|=0,X,Y属于R}=
如题{(X,Y)|(X+2)2+|Y-3|=0,X,Y属于R}=
(x+y)/y=8/3则x/y=__ y/x-y=___
(x+y)/y=8/3则x/y=__ y/x-y=___
考考你:二元一次方程1.X-Y=-5,3X+2Y=10 2.3X-Y=7,5X+2Y=8
x不等于y,比大小:x^4-x^3*y与x*y^3-y^4如题