(1/6)x+[1/6x+24]×150%怎么解呀?(1/6)x+[1/6x+24]×150%=(1-1/4)x

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/05 03:21:50
(1/6)x+[1/6x+24]×150%怎么解呀?(1/6)x+[1/6x+24]×150%=(1-1/4)x(1/6)x+[1/6x+24]×150%怎么解呀?(1/6)x+[1/6x+24]×1

(1/6)x+[1/6x+24]×150%怎么解呀?(1/6)x+[1/6x+24]×150%=(1-1/4)x
(1/6)x+[1/6x+24]×150%怎么解呀?
(1/6)x+[1/6x+24]×150%=(1-1/4)x

(1/6)x+[1/6x+24]×150%怎么解呀?(1/6)x+[1/6x+24]×150%=(1-1/4)x
1/6x+(1/6x+24)*1.5=3/4x
1/6x+(1/6x+24)*(3/2)=3/4x
1/4x+1/6x+36=3/4x
1/3x=36
x=108

解九宫格题目(X为未知数)9 X 2 X 7 X 8 X XX X 4 X X 9 X 6 X1 3 X 5 X X X X 24 X X 8 5 X X 1 XX 8 9 4 X 1 6 7 XX 1 X X 3 6 X X 88 X X X X 2 X 3 6X 5 X 6 X X 9 X XX X 7 X 4 X 2 X 1 (x²+x-1)(x²+x)=6则x²+x+2的值 *-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || 跪求1到6年级语文书(人民教育出版社)上的日积月累以及古诗词格式:一年级上下册古诗词:X X X X X X X X X X 二年级上下册古诗词:X X X X X X X X X X 三年级上下册古诗词:X X X X X X X X X X .( 填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x x x 3 x x x x 1 8x x x 9 x 1 x x x2 1 x x x x 6 x x x 6 x 7 x 3 x x 1 x x 9 x 2 x x x 47 x x 8 x x 5 x x x-(a+1)x+a 6x+7x+2 (-8x的平方+6x)-(5x的平方-4x+1) 解方程:(X/X-1)²-(X/X-1)+6=0 x(x+1)-6(x+1)+9x因式分解 计算3/X-6/1-X-X+5/X的平方-X 求分式1/(x²+x)+1/(x²+3x+2)+1/(x²+5x+6)+1/(x²+7x+12)+1/(x²+9x+20)的值 解方程6^x+4^x=9^x,9^(-x)-2*3^(1-x)=27 多项式x^4+2x^3-4x^2-2x+3与x^3+4x^2+x-6的最大公因式是什么x^4+2x^3-4x^2-2x+3=(x^4+3x^3)-x(x^2+4x+3)+(x+3)=x^3(x+3)-x(x+1)(x+3)+(x+3)=(x+3)[x^3-x(x+1)+1]=(x+3)[x^3+1-x(x+1)]=(x+3)[(x+1)( 已知f(x-1)=x²+4x-5则f(x)的表达式是() A x²+6x B x²+8x+7已知f(x-1)=x²+4x-5则f(x)的表达式是()A x²+6xB x²+8x+7C x²+2x-3D x²++6x-10 0.3x+7x-0.25x=21.58.7×(36-x)=04(不知道是x还是× 都解了吧)x或者×(x+0.2)=1.27(x+6)-3x=4x(2x+5)3(x+2)=4(x+1)18-4x=2x-63.8x+1.2x=256x+1.5x=15呼呼.累死我了 着急 (1/x²+3x+2)+(1/x²+5x+6)+(1/x²+4x+3) 求解 1/X(X+3)+1/(X+5)(X+6)+……+1/(X+99)(X+100) 计算(x*x+4x+5)/(x+2)-(x*x+6x+10)/(x+3)+1