double a=0.0,b=1.1;

double a=0.0,b=1.1; #includeusing namespace std;#define PI 314159double area(double radius=0);double area(double a,double b);double area(double a,double b,double h);double area(double a,double b,double c,int);int main(){cout operator=是什么意思啊# include double sum(double a,double b);double subtract(double a,double b);double divide(double a,double b);double multiply(double a,double b);main(){int choice;char operator;double a,b;double (*func)();printf( * * * * * double b = Convert.ToDouble(a?0); int b(double l,double r) { double a; aint b(double l,double r){double a;a=(l+r)/2;if(a*a-6>0) b(l,a);else if(a*a-6 C语言,double a=3 double b=3.0 double b=3.00C语言,double a=3 double b=3.0 double b=3.00 这3个都正确吗? c报错 invalid operands of types 'double' and 'double()(double)' to binary 'operator/'是怎么回事啊double mutual(double a,double b,double f){double y;y=(-(b*a+f*(1-a))*log(b*a+f*(1-a))-((1-b)*a+(1-f)*(1-a))*log((1-b)*a+(1-f)*(1-a))-a*(-b*log(b) c++习题 10.下列函数定义中正确的是( ).请解析一下每个选项.还有正确答案A.double fun(double &x,double &y) B.double fun(double &x,double &y){ {double z; return *x/*y;z=x/y; }return z;}C.double fun(double *x,double *y) D.double C语言简单计算器,支持加减乘除乘方运算,每步要有注释,求助C语言高手解决,谢谢!#include double add(double a,double b){ double s; s=a+b; return s;}double sub(double a,double b){ double s; s=a-b; return s;}double multi( C语言写的计算器中如何加入复数的运算?只能计算实数的加减乘除 怎么加入复数的运算#include double add(double a,double b){ double s; s=a+b; return s;}double sub(double a,double b){ double s; s=a-b; return s;}double mult 二分法的问题#include #include #include #define MIN 0.001double f (double a,double b){double c;c = (sin(a) - a*a/4) * (sin(b) - b*b/4);printf ( c is :%lf ,c);return c;}double erfen( double a ,double b){double n;n = a - b;printf ( n is :%lf C语言选择题,看不懂答案.求解释#includemain(){double a[15],k;k=fun(a);}则以下选项中错误的fun函数首部是 ( D)A.double fun(double a[15]) B.double fun(double *a)C.double fun(double a[]) D.double fun(double 函数指针可以指向返回值相同但参数个数不同的函数吗?#include double f1(double x){ return x*x; }double f2(double x,double y){ return x*y; }double fun(double a,double b){//f = f2 ; r2 = (*f)(a,b);return r1 + r2;}main(){ double x1=5 这个c程序哪错了?求二元一次方程解的.#include#includevoid prin();double xone(double,double,double);double xtwo(double,double,double);int main(void){double a,b,c,i,value1,value2;print();scanf(%fx2+%fx+%f=%f,&a,&b,&c,&i);printf(you inp 【c++】现有三个函数（1）double Add(double a) (2)double Add(double a,double b) (3)……如题,(3) int Add(double a,double b,double c=0)现在对Add函数进行调用,编译出现错误的是A.Add(3) B.Add(3.3,3.4) C.Add(2.3,3.1,3.2) D.Add(3 C语言 一个定义函数 求详解.double fx（double）{return exp（x）；｝double intf（double （*f）（double）,double a,double b,int n）{double sum,h；int i；h=（b-a）/n;sum=(f(a)+f(b))/2.0;for (i=1;i 这个C++梯形法求定积分的函数为什么错了double tixing(double (*f)(double),double a,double b){int n=1000,i;double s,sum=0,d;d=(b-a)/n;double y1=(*f)(a+i*d);double y2=(*f)(a+i*d-d);for (i=1;i .指出正确的表达式A double a=1.0; B Double a=new Double(1.0); C byte a = 340; D Byte a = 120;