计算(4mn-m^2-4n^2)/(2n-m)
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/26 10:27:40
计算(4mn-m^2-4n^2)/(2n-m)计算(4mn-m^2-4n^2)/(2n-m)计算(4mn-m^2-4n^2)/(2n-m)(4mn-m^2-4n^2)/(2n-m)=-(2n-m)^2
计算(4mn-m^2-4n^2)/(2n-m)
计算(4mn-m^2-4n^2)/(2n-m)
计算(4mn-m^2-4n^2)/(2n-m)
(4mn-m^2-4n^2)/(2n-m) = - (2n-m)^2/(2n-m)=-(2n-m) =m-2n
(4mn-m^2-4n^2)/(2n-m) = - (2n-m)^2/(2n-m)=-(2n-m)
(7m^2-4mn-n^2)-2(2m^2-mn+2n^2)计算.
计算:[-m^3n/(m-n)^2]^4*[(n^2-mn)/m]^3/m^4n^10*[(mn-n^2)/m]^6
计算(-2mn)^3(mn+1/2)(m^2n^2-1/2mn+1/4)
计算(-3m^2/4n^2)/6mn^4
计算 (-n^2/m)^4除以(-mn^4)
计算 (-n^2/m)^4除以(-mn^4)
计算m/(m+n)+(mn)/(n^2 -m^2)
若m-n=7,mn=5求(3m-5n+4mn)-(2m-4n+6mn)要计算过程]
计算(-mn)^2×(-m^2n)^3
计算(4mn-m^2-4n^2)/(2n-m)
计算(2m+n)(4m^2-2mn+n^2)
计算(2m-3n)(4m^2+6mn+9n^2)
如何计算(2m-n)(4m的平方+2mn+n的平方)快
计算【(m+n)2-(m-n)2】÷4mn的结果是
计算[(m+n)的2次方-(m-n)的2次方]÷4mn结果
2mn[(2mn)^2-3n(mn+m^2*n)-mn^2]计算
计算4﹙m√n/m+2/n√mn³﹚-3﹙n√m/n+m/1√m³n﹚=
m-n=7 mn=-5求(3m+5n+4mn)-(2n-4n+6mn)