m-n_2=2 2m+3n=12yiyuanyicifangchengjian
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/29 17:24:14
m-n_2=22m+3n=12yiyuanyicifangchengjianm-n_2=22m+3n=12yiyuanyicifangchengjianm-n_2=22m+3n=12yiyuanyic
m-n_2=2 2m+3n=12yiyuanyicifangchengjian
m-n_2=2 2m+3n=12
yiyuanyicifangchengjian
m-n_2=2 2m+3n=12yiyuanyicifangchengjian
你的问题是这样的吗?
m-n/2=2 --------(1)
2m+3n=12 -------(2)
解这个方程二元一次方程组?
(1)*6 + (2)
==> (m-n/2)*6 + (2m+3n) = 2*6 + 12
==> 8m = 24
==> m = 3
将m=3 代入方程式(1) 得到:
3 - n/2 = 2;
==> n = 2
m-n_2=2 2m+3n=12yiyuanyicifangchengjian
lim(x→0)an^2+3n_2/(n_1)^2=3.求a.
几题填空题1、当m=_______时,多项式(m+2)x^|m-2|-4x^2+3表示四次三项式.2、已知关于x的多项式(n_2)x^2-(m-3)x+4的一次项系数是2,则这个多项式是________.
(m-n)^3(n-m)^2(m-n)=_____
(3m-n)(m-2n)=()
已知3m=4n,则m/m+n+n/m-n-m^2/m^2-n^2=
m/n=5/3,求(m/m+n)+(m/m+n)-(n^2/m^2-n^2)
已知m/n=5、,求(m/(m+n))+(m/(m-n))-(n^2/(m^3-n^2))
已知3m=2n,则m/(m+n)+n/(m-n)-n^2/(m^2-n^2)=?
2m+3n+2m+3n+m+2m+3n+n=______
(m-2n)(2n+m)-(-3m-4n)(4n-3m)=
(m-2n/n-m)-(n/m-n)=
.4(m+n)^2*(m+n)^3-7(m+n)(m+n)^4+5(m+n)^5=
m-{n-2m+[3m-(6m+3n)+5n]}=
(m-n)(m+n)+(m+n)²-3=2m²
已知m,n都为自然数,且m(m-n)-n(n-m)=12,求m,n的值.∴(m-n)(m+n)=1×12=2×6=3×4这步是怎么回事
分解因式:(1)6a(m-n)^2-8a^2 (m-n)^3 (2)已知m、n均为整数,且有m(m-n)-n(n-m)=12,求m、n的值
(m-n)^2*(m-n)^4=?