设f '(sinx^2)=cos2x+tanx^2 (0
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设f''(sinx^2)=cos2x+tanx^2(0设f''(sinx^2)=cos2x+tanx^2(0设f''(sinx^2)=cos2x+tanx^2(0f''(sinx^2)=cos2x+tanx^
设f '(sinx^2)=cos2x+tanx^2 (0
设f '(sinx^2)=cos2x+tanx^2 (0
设f '(sinx^2)=cos2x+tanx^2 (0
f '(sinx^2)=cos2x+tanx^2=1-2sinx^2+(sinx^2)/(1-sinx^2)
therefore
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