若0
来源：学生作业帮助网 编辑：六六作业网 时间：2024/11/22 07:08:47
若0若0若0tanx=1/7,tany=3/4则tan(x+y)=(tanx+tany)/(1-tanxtany)=(1/7+3/4)/[1-(1/7)*(3/4)]=1又0＜x＜π/2,0＜y＜π/
若0
若0
若0
tanx=1/7,tany=3/4
则tan(x+y)=(tanx+tany)/(1-tanxtany)=(1/7+3/4)/[1-(1/7)*(3/4)]=1
又0＜x＜π/2,0＜y＜π/2
则0＜x+y＜π
所以x+y=π/4
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tan(x+y)=(tany+tanx)/(1-tanx*tany)
tan(x+y)=1
and 0