若5x^2-7xy-6y^2=0,求5x/3y的值
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若5x^2-7xy-6y^2=0,求5x/3y的值若5x^2-7xy-6y^2=0,求5x/3y的值若5x^2-7xy-6y^2=0,求5x/3y的值5x^2-7xy-6y^2=0[十字相乘](5x+
若5x^2-7xy-6y^2=0,求5x/3y的值
若5x^2-7xy-6y^2=0,求5x/3y的值
若5x^2-7xy-6y^2=0,求5x/3y的值
5x^2-7xy-6y^2=0
[十字相乘]
(5x+3y)(x-2y)=0
5x=-3y 或 x=2y
5x=-3y时
5x/3y=-3y/3y=-1
x=2y时
5x/3y=10y/3y=10/3
原式可化为(5x+3y)(x-2y)=0,因此5x+3y=0或者x-2y=0,即5x=-3y或者x=2y,所以5x/3y=-1或者10/3
对等式5x^2-7xy-6y^2=两边同除以xy,得
5x/y-7-6y/x=0
5(x/y)-6(y/x)=7
令x/y=a
则y/x=1/a
5a-6/a=7
5a^2-6=7a
5a^2-7a-6=0
(5a+3)(a-2)=0
a=-3/5或a=2
当a=-3/5时,x/y=-3/5
5x/3y=(5/3)(x/y)=(5/3)(-3/5)=-1
当a=2,x/y=2
5x/3y=(5/3)(x/y)=2*(5/3)=10/3
你可以采用十字相乘方法
然后将这个式子
分解成(5x + 3y)(x - 2y) = 0
即5x= -3y 或者 x = 2y
所以 5x/3y = -1 或者10/3
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