若2a-1>a-4,11a-5

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若2a-1>a-4,11a-5若2a-1>a-4,11a-5若2a-1>a-4,11a-5若2a-1>a-4,11a-5a-4得a>-3则a+3>011a-5|a+3|-|5a-3|=a+3-(3-5

若2a-1>a-4,11a-5
若2a-1>a-4,11a-5

若2a-1>a-4,11a-5
若2a-1>a-4,11a-5a-4
得a>-3 则a+3>0
11a-5

|a+3|-|5a-3|=a+3-(3-5a)=6a

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