已知|ab-2|与|b-1|互为相反数,求代数式:1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+······+1/(a+2013)*(b+2013)的值

来源：学生作业帮助网编辑：六六作业网时间：2024/12/23 08:54:07

已知|ab-2|与|b-1|互为相反数,求代数式:1/ab+1/(a+1)*(b+1)+1/(a+2)*(b+2)+······+1/(a+2013)*(b+2013)的值已知|ab-2|与|b-1|

已知|ab-2|与|b-1|互为相反数,求代数式:1/ab+1/(a+1)*(b+1)+1/(a+2)*(b+2)+······+1/(a+2013)*(b+2013)的值
已知|ab-2|与|b-1|互为相反数,求代数式:1/ab+1/(a+1)*(b+1)+1/(a+2)*(b+2)+···
···+1/(a+2013)*(b+2013)的值

已知|ab-2|与|b-1|互为相反数,求代数式:1/ab+1/(a+1)*(b+1)+1/(a+2)*(b+2)+······+1/(a+2013)*(b+2013)的值
|ab-2|=|b-1|=0
a=2,b=1
1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+…+1/(a+2013)(b+2013)
=1-1/2015=2014/2015