(1)已知X/3=Y/2=Z/5 求 XY+YZ+ZX/X^2Y^2Z^2 的值 (2)已知1-a/ab =3 求(3a-1)(3b+1)+1/b-a+12ab的值
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(1)已知X/3=Y/2=Z/5求XY+YZ+ZX/X^2Y^2Z^2的值(2)已知1-a/ab=3求(3a-1)(3b+1)+1/b-a+12ab的值(1)已知X/3=Y/2=Z/5求XY+YZ+Z
(1)已知X/3=Y/2=Z/5 求 XY+YZ+ZX/X^2Y^2Z^2 的值 (2)已知1-a/ab =3 求(3a-1)(3b+1)+1/b-a+12ab的值
(1)已知X/3=Y/2=Z/5 求 XY+YZ+ZX/X^2Y^2Z^2 的值 (2)已知1-a/ab =3 求(3a-1)(3b+1)+1/b-a+12ab的值
(1)已知X/3=Y/2=Z/5 求 XY+YZ+ZX/X^2Y^2Z^2 的值 (2)已知1-a/ab =3 求(3a-1)(3b+1)+1/b-a+12ab的值
1、设x/3=y/2=z/5=k,则x=15k,y=10k,z=25k,所以,(xy+yz+zx)/(x²+y²+z²)=(150k²+250k²+375k²)/(225k²+100k²+625k²)=31/38.
2、(1-a)/ab=3,则ab=(1-a)/3,则[(3a-1)(3b+1)+1]/[b-a+12ab]=[9ab-3b+3a]/[12ab-a+b]=[3(1-a)+3a-3b]/[4(1-a)-a+b]=(3-3b)/(4-5a+b)=……….
同学,你是不是一些符号忘了加上去,比如说括号,这样别人都不知道你要求的是什么
第一题出错了应该是(xy+yz+zx)/(x^2+y^2+z^2)=31/38; 因为由题意可设x=3k,y=2k,z=5k,将它们代入要求的式子中,消去k^2即可;
由已知可得,3b=(1-a)/a, 3ab=1-a, 1/b=(1-a)/(3a),将这些代入要求的式子中,消去a即可……
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