已知2sin(3π+φ),求2sin²φ+3sinφcosφ-cos²φ的值
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已知2sin(3π+φ),求2sin²φ+3sinφcosφ-cos²φ的值已知2sin(3π+φ),求2sin²φ+3sinφcosφ-cos²φ的值已知2s
已知2sin(3π+φ),求2sin²φ+3sinφcosφ-cos²φ的值
已知2sin(3π+φ),求2sin²φ+3sinφcosφ-cos²φ的值
已知2sin(3π+φ),求2sin²φ+3sinφcosφ-cos²φ的值
因为:2sin{3π+α}=cos{π+α},所以:-2sinα=-cosα,则:tanα=1/2
所以:2sin^2α+3sinαcosα-cos^2α
=(2sin^2α+3sinαcosα-cos^2α)/(sin^2α+cos^2α)
=(2tan^2α+3tanα-1)/(tan^2α+1)
=4/5
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