log以7为底[ log以3为底(log以2为底x) ]=0,则x^1/2等于
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log以7为底[log以3为底(log以2为底x)]=0,则x^1/2等于log以7为底[log以3为底(log以2为底x)]=0,则x^1/2等于log以7为底[log以3为底(log以2为底x)]
log以7为底[ log以3为底(log以2为底x) ]=0,则x^1/2等于
log以7为底[ log以3为底(log以2为底x) ]=0,则x^1/2等于
log以7为底[ log以3为底(log以2为底x) ]=0,则x^1/2等于
解析,
log(7)[log(3){log(2)x}]=0=log(7)1
因此,
log(3)[log(2)x]=1=log(3)3
因此,
log(2)x=3
即是,x=8
x^(1/2)=2√2.
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