若lim(1-(2*3^n)/(x^n+3^n))=-1,则x的取值范围是

求极限lim(x→∞)（1/n+2/n+3/n..+n/n） 求极限lim(-2)^n+3^n/(-2)^[n+1]+3^[n+1] (x→∞) lim x趋向于无穷 (2^n+1+3^n+1)/(2^n+3^n)= 大学微积分的题目 lim(x→∞)(1^n+2^n+3^n)^1/n 求极限Lim（(n-x)/(n+2))^(n+1) lim(n+3)(4-n)/(n-1)(3-2n) lim(n^3+n)/(n^4-3n^2+1) lim[(n+3)/(n+1))]^(n-2) 【n无穷大】 lim(2^n+3^n)^1 (n趋向无穷) lim(cos1/n)^n^2 n->∞lim (1+|x|)^1/x x->0 若lim(1-(2*3^n)/(x^n+3^n))=-1,则x的取值范围是 数列 极限 证明证明：若(1)y(n+1)>y(n)(2)lim yn->∞(3)lim(x(n+1)-x(n))/(y(n+1)-yn)存在那么lim xn/yn=lim(x(n+1)-x(n))/(y(n+1)-yn) 求极限,lim(x->0) (1-2sinx)^(3/x)lim(n->+∞) (n!-4^n) / (6+ln(n)+n^2) 求极限 x→∞lim(3^n+1)/(3^(n+1)+2^n)= lim(x→∞）1+2+3+…+n/(n+2)(n+4)=? 高数求极限 lim(x→0)(2^n+3^n)^1/n 感谢回答! lim(n/(n^2+1)+...+n/(n^2+n))x趋向于无穷 求解答过程~ 求1.lim(3n-(3n^2+2n)/(n-1)) 2.lim(8+1/(n+1)) 3.lim根号n(根号(n+1)-根号(n-3))