计算:cos(π/5)+cos(2π/5)+cos(3π/5)+cos(4π/5)
来源:学生作业帮助网 编辑:六六作业网 时间:2025/02/07 09:57:42
计算:cos(π/5)+cos(2π/5)+cos(3π/5)+cos(4π/5)计算:cos(π/5)+cos(2π/5)+cos(3π/5)+cos(4π/5)计算:cos(π/5)+cos(2π
计算:cos(π/5)+cos(2π/5)+cos(3π/5)+cos(4π/5)
计算:cos(π/5)+cos(2π/5)+cos(3π/5)+cos(4π/5)
计算:cos(π/5)+cos(2π/5)+cos(3π/5)+cos(4π/5)
一楼的简直是太神了,不要那么解
cos(π/5)+cos(2π/5)+cos(3π/5)+cos(4π/5)
=cos(π/5)+cos(π-3π/5)+cos(3π/5)+cos(π-π/5)
=cos(π/5)-cos(3π/5)+cos(3π/5)-cos(π/5)
=0
计算:cos(π/5)+cos(2π/5)+cos(3π/5)+cos(4π/5)
计算cos(π/5)cos(2π/5)的值
计算cos(a+5π/12)cos(a+π/6)+cos(π/12-a)cos(π/3-a)
求值:cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)
求值:cos(π/11)-cos(2π/11)+cos(3π/11)-cos(4π/11)+cos(5π/11)
cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)
计算cos(π/3+arcsin4/5)=?
计算∫[-2/π,2/π]cos^5dx
cos^2 π/8+cos ^2 3π/8+ cos^2 5π/8+cos^2 7π/8=?
[sin(5π-α)cos(-π-α)]/[cos(α-π)cos(π/2+α)]化简
cosθ^2+cos(θ+2π/3)^2+cos(θ-2π/3)^2 计算
【紧急求助】计算:cosα+cos(2π/3 +α)+cos(4π/3 +α)
已知sin a=2cos a 计算⑴(sinα+2cosα)/(5cosα-sinα) ⑵tan(α+π/4)
cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)怎么解
计算cos平方π/12-1/2
Cos[π/7] + Cos[2 π/7] + Cos[3 π/7] + Cos[4 π/7] + Cos[5 π/7] + Cos[6 π/7] + Cos[7π/7]过程思路 不要只有答案哦
三角函数求值(急)哪个高手帮忙求一下Cos(π/3)Cos(π2/3) 要计算出来的 不要查表的刚搞错了 不好意思 是Cos(π/5)Cos(π2/5)
已知tan(α+π/4)=3,计算2sinαcosα+6cos方α-3/5cos方α-6sinαcosα-5sin方α