main() { int a=1,b=2,c=2,t; while(a

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main(){inta=1,b=2,c=2,t;while(amain(){inta=1,b=2,c=2,t;while(amain(){inta=1,b=2,c=2,t;while(a注意循环条件:

main() { int a=1,b=2,c=2,t; while(a
main() { int a=1,b=2,c=2,t; while(a

main() { int a=1,b=2,c=2,t; while(a
注意循环条件:while(a

#include int b=2; int fun(int *k) {b=*k+b;return(b);} main() {int a[10]={1,2,3,4,5,6,7,8}, main() { int a,b,c; a=1;b=2;c=3; if(a #include int b=2; int fun(int*k) { b=*k+b;return(b);} main() {int a[10]={1,2,3,4,5,6,7,8}#include int b=2; int fun(int*k) { b=*k+b;return(b);} main() {int a[10]={1,2,3,4,5,6,7,8},i;for(i=2;i void fun(int a,int b) { int t; t=a;a=b;b=t; } main()void fun(int a,int b){ int t; t=a;a=b;b=t; } main() { int c[10]={1,2,3,4,5,6,7,8,9,0}.i; for(i=0;i main() { int a=2,b=-1,c=2; if(a main() { int a=1,b=2,c=2,t; while(a #include main( ) { int a=1,b=2; for(;a #include void main() { int a=1 b=2 c=3 cout #include void f(int*x,int y) {*x=y+1;y=*x+2;} main() {int a=2,b=2; f(&a,b); printf(%d %d#includevoid f(int*x,int y){*x=y+1;y=*x+2;}main(){int a=2,b=2;f(&a,b);printf(%d %d,a,b);} .main() { int a=1,b=10; do {b-=a;a++;}while(b-- 矩阵相加(C++)#include using namespace std; const int rows=3;const int cols=3;void matrixadd(int *,int *,int *,int,int);int main(){int a[rows][cols]={{1,3,5},{7,8,11},{13,15,17}};int b[rows][cols]={{9,8,7},{6,5,4},{3,2,1}};int c[rows][cols]={0 error C2065:'a' :undeclared identifier#includeint main(){int print_shang();int print_xia();print_shang();print_xia();return 0;}int print_shang(){int a,b;for(a=1;a main() { int x=1,y=2,z=3; int r; r=func(x+y+z,x++,++y); printf(%d,r); } int func(int a,int b,intint func(int a,int b,int c){int d;d=a+b+c;return d;} 请问一下“void main() {int t,a,b,c;a=1;b=2;c=2; while(a main() {int a,b; for (a=1,b=1;a #include void fun(int a, int b) { int t; t=a; a=b; b=t;main() { int c[10]={1,2,3,4,5,6,7,8,9,0), i; for (i=0; i #include void fun(int a,int b) {int t; t=a;a=b;b=t; } main() {int c[6]={1,2,3,4,5,6},i;for(i=0;i int func(int x,int y ) { return(x+y) } main() {int a=1,b=2,c=3,d=4,e=5;printf(&d ,func((a+b,b+c,c+a),(d+e)));