2x+3y=15 (x+1)/7=(y+4)/5二元一次方程 2x+3y=15 x+1/7=y+4/5
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2x+3y=15(x+1)/7=(y+4)/5二元一次方程2x+3y=15x+1/7=y+4/52x+3y=15(x+1)/7=(y+4)/5二元一次方程2x+3y=15x+1/7=y+4/52x+3
2x+3y=15 (x+1)/7=(y+4)/5二元一次方程 2x+3y=15 x+1/7=y+4/5
2x+3y=15 (x+1)/7=(y+4)/5
二元一次方程 2x+3y=15 x+1/7=y+4/5
2x+3y=15 (x+1)/7=(y+4)/5二元一次方程 2x+3y=15 x+1/7=y+4/5
2x+3y=15 (1)
(x+1)/7=(y+4)/5 (2)
由(2)得:
5x--7y=23 (3)
(1)x5--(2)x2得:
29y=29
y=1
把y=1代入(1)得:
2x+3=15
x=6
所以 原方程组的解是:x=6
y=1.
解
(x+1)/7=(y+4)/5
5(x+1)=7(y+4)
5x-7y=23 ①
2x+3y=15 ②
①×3得:15x-21y=69 ③
②×7得:14x+21y=105 ④
③+④得:29x=174
∴x=6
将x=6代入②得:12+3y=15
∴y=1
∴x=6,y=1
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