(2,-1,-1,1,2;1,1,-2,1,4;4,-6,2,-2,4;3,6,-9,7,9)怎样化为行阶梯形矩阵
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(2,-1,-1,1,2;1,1,-2,1,4;4,-6,2,-2,4;3,6,-9,7,9)怎样化为行阶梯形矩阵(2,-1,-1,1,2;1,1,-2,1,4;4,-6,2,-2,4;3,6,-9,
(2,-1,-1,1,2;1,1,-2,1,4;4,-6,2,-2,4;3,6,-9,7,9)怎样化为行阶梯形矩阵
(2,-1,-1,1,2;1,1,-2,1,4;4,-6,2,-2,4;3,6,-9,7,9)怎样化为行阶梯形矩阵
(2,-1,-1,1,2;1,1,-2,1,4;4,-6,2,-2,4;3,6,-9,7,9)怎样化为行阶梯形矩阵
r3-2r1,r1-2r2,r4-3r2
0 -3 3 -1 -6
1 1 -2 1 4
0 -4 4 -4 0
0 3 -3 4 -3
r3*(-1/4),r1+3r3,r4-3r3
0 0 0 2 -6
1 1 -2 1 4
0 1 -1 1 0
0 0 0 1 -3
r1-2r4
0 0 0 0 0
1 1 -2 1 4
0 1 -1 1 0
0 0 0 1 -3
交换行
1 1 -2 1 4
0 1 -1 1 0
0 0 0 1 -3
0 0 0 0 0
1 1 -2 1 4
0 1 -1 1 0
0 0 0 1 -3
0 0 0 0 0
1 2 1 2 () () ()()
1+1/2^2
1+2+1+2+1+2+1+2+1+2+1+2+1+2 =( )*( ) =()
1 1 1 1 1 1 1 1 1 1 1 -+-2 2
(1-1/2^2)(1-1/3^2)(1-1/4^2).(1-1/2009^2),
(1+1/2+1/3+...
计算行列式 2 1 1 1 ,1 2 1 1 ,1 1 2 1,1 1 1 2,
1/2-1/(n+1)
证明 1+1/1+1/1*2+1/1*2*3+.+1/1*2*3*...*n
[(1+2^-(1/32)]*[(1+2^-(1/16)]*[(1+2^-(1/8)]*[(1+2^-(1/4)]*[(1+2^-(1/2)]
(1-1/2^2)*(1-1/3^2)*(1-1/4^2)*.*(1-1/2002^2)*(1-1/2003^2)
(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)(1+1/2^16),
1*1/2=?
1+1+2+56
5,2,1,1,
1/2+56/1
1.1/2.
2x-1-1