g(x)=e^x,f(x)=g[λx+(1-λ)a]-λg(x) a,λ为常数,且0

设f(x)=1(|x|1);g(X)=e^x,求f[g(x)]和g[f(x)]. 若f(x)=(e^x-e^-x)/2,g(x)=(e^x+e^-x)/2,则用f(x),g(x)表示f(2x)的结果是? f(x)=e^x-e^-x,g(x)=e^x+e^-x,e=2.71（1）若f(x)f(y)=4,g(x)g(y)=8,求g(x+y)/g(x-y)? | f(x) | / | g(x) | = | f(x)/g(x) | 吗? 已知函数f(x)=e^x-e^-x,g(x)=e^x+e^-x 设f(x)f(y)=4,g(x)g (y)=8,求g(x+y)/g(x-y) f(x)=e^x-e^-x,g(x)=e^x+e^-x,e=2.71,(1){f(x)}^2+{g(x)}^2的值? max{f(x),g(x)}=1/2(f(x)+g(x)+|f(x)-g(x)| 证明(f(x)*g(x))'=f'(x)*g(x)+g'(x)*f(x) 证明(f(x)*g(x)）'=f(x)'*g(x)+g(x)'*f(x) f(x)=x/e^x ,g(x)= (2-X)e^x/e^2 求证:当x>1时,f(x)>g(x) 帮帮忙f(x)=e^x,g(x)=lnx.求证g(X) g(x)=f(x)/e^x,则g'(x)等于 已知f(x)=e^x-e^-x,g(x)=e^x+e^-x,设f(x)f(y)=4,g(x)(y)=8,求[g（x+y）]/[g（x-y）]的值 f[g(x)]=f(x)*g(x)? 有f(x),g(x),f'(x)=g(x),g'(x)=2e^x-f(x)已知f(0)=0,g(0)=2.求f(x),g(x). 已知F(x)=eX—e-X,g(x)=eX+e-X,（e=2.71828） 设F(x)F(y)=4,g(x)g(y)=8,求g(x+y)除以g(x-y)? f(x)=(1-x)e^x-1,g(x)=f(x)/x证明g(x)有最大值g(t)且-2 f(x)=2x-1,g(x)=x^2,则f[g(x)]=?,g[f(x)]=?,f[f(x)]=?,g[g(x)]=?