3.228*(-9)+(3.272)*9-(-1.5)*9
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3.228*(-9)+(3.272)*9-(-1.5)*93.228*(-9)+(3.272)*9-(-1.5)*93.228*(-9)+(3.272)*9-(-1.5)*93.228*(-9)+(3
3.228*(-9)+(3.272)*9-(-1.5)*9
3.228*(-9)+(3.272)*9-(-1.5)*9
3.228*(-9)+(3.272)*9-(-1.5)*9
3.228*(-9)+(3.272)*9-(-1.5)*9
=(-3.228)*9+(3.272)*9+1.5*9
=(-3.228+3.272+1.5)*9
=1.544*9
=13.896
3.228*(-9)+(3.272)*9-(-1.5)*9
=9*(-3.228+3.272+1.5)
=9*1.544
=13.896
3.228*(-9)+(3.272)*9-(-1.5)*9
3.228x(-9)+(-3.272)x9-(-1.5)x9
99又9分之8×(-18) 3.228x×(-9)+(-3.272)×9-(-1.5)×9
3.228×(﹣9)+(﹣3.272)×9-(﹣1.5)×9
3.228×(-9)+(-3.772)×9-(-1.5×9)
3.228x(-9)+(-3.272)x9-(-1.5)x9= 11.35x(-2/3)²+1.05x(-2²/9)-7.7x(-4/3²)=215+126x214÷215x126+89=赶紧来人啊
3.288乘-9+(-3.272)乘9-( -1.5)乘9简算
3.228×(-9)+(-3.772)×9-(-1.5)×9
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谁能告诉我下面两题的简便算法-3.228×(-9)-(-3.772)×9+(-1.5)×9(99+15/16)×(-8)我刚刚学习有理数乘除法...还不太明白 谁能告诉我以上题目的简便算法...
-3.228*(-9)-(-3.772)*9+(-1.5)*9 (99+15/16)*(-8) 已知a,b互为相反数,c,d互为倒数m的绝对是三求-4/9(ab)+m-cd的值-1,-3,-5,-7,8---第009个是多少?规定#表示一种运算,若a#b=a-2b/ab,试求3#(4#1/2)的值
(1/2-3+5/6-7/12)×(-36)(2又1/3-238/54+91/117)×(-1又2/7)3.228×(-9)+(-3.772)×9-(-1.5×9)(1-1/2)(1/3-1)(1-1/4)(1/5-1)…(1/2009-1)(1-1/2010)
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