若xy=3,x^2+y^2=10,求x+y与x-y的值

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若xy=3,x^2+y^2=10,求x+y与x-y的值若xy=3,x^2+y^2=10,求x+y与x-y的值若xy=3,x^2+y^2=10,求x+y与x-y的值解.﹙x+y﹚=x²+2xy

若xy=3,x^2+y^2=10,求x+y与x-y的值
若xy=3,x^2+y^2=10,求x+y与x-y的值

若xy=3,x^2+y^2=10,求x+y与x-y的值
解.﹙x+y﹚=x²+2xy+y²=16,x+y=±4.
﹙x-y﹚²=x²-2xy+y²=4 x-y=±2

(x+y)^2=x^2+y^2+2xy;
(x-y)^2=x^2+y^2-2xy;
xy=3,那就是xy同正负咯，接下来你自己算咯，不用我算了吧
很多种答案，自己看看呗

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