x^5-3x^3-28因式分解因式分解x^5-3x^3-28x3a^2x-4b^3y+3b^3x-4a^3y(ax+by)^2+(bx-ay)^2

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x^5-3x^3-28因式分解因式分解x^5-3x^3-28x3a^2x-4b^3y+3b^3x-4a^3y(ax+by)^2+(bx-ay)^2x^5-3x^3-28因式分解因式分解x^5-3x^3

x^5-3x^3-28因式分解因式分解x^5-3x^3-28x3a^2x-4b^3y+3b^3x-4a^3y(ax+by)^2+(bx-ay)^2
x^5-3x^3-28因式分解
因式分解
x^5-3x^3-28x
3a^2x-4b^3y+3b^3x-4a^3y
(ax+by)^2+(bx-ay)^2

x^5-3x^3-28因式分解因式分解x^5-3x^3-28x3a^2x-4b^3y+3b^3x-4a^3y(ax+by)^2+(bx-ay)^2
x^5-3x^3-28x
=x(x^4-3x^2-28)
=x(x^2-7)(x^2+4)
3a^2x-4b^3y+3b^3x-4a^2y
=a^2(3x-4y)+b^3(3x-4y)
=(3x-4y)(a^2+b^3)
(ax+by)^2+(bx-ay)^2
=a^2x^2+2abxy+b^2y^2+b^2x^2-2abxy+a^2y^2
=a^2x^2+b^2y^2+b^2x^2+a^2y^2
=(a^2x^2+b^2x^2)+(b^2y^2+a^2y^2)
=x^2(a^2+b^2)+y^2(b^2+a^2)
=(a^2+b^2)(x^2+y^2)

x(x+根号7)(x-根号7)(x^2+4)
3x(a^2+b^3)-4y(b^3+a^3)(你是否打错了呀,否则的话应该是)
=3x(a^3+b^3)-4y(b^3+a^3)
=(a^3+b^3)(3x-4y)
(ax)^2+(by)^2+2abxy+(bx)^2+(ay)^2-2abxy
=a^2(x^2+y^2)+b^2(x^2+y^2)
=(a^2+b^2)(x^2+y^2)

X^5-3X^3-28X
=(X^3+4X)(X^2-7)
=X(X^2+4)(X^2-7)
第二题打错了吧
3a^2x-4b^3y+3b^3x-4a^2y
=a^2(3x-4y)+b^3(3x-4y)
=(a^2+b^3)(3x-4y)
(ax+by)^2+(bx-ay)^2
=(ax)^2+2abxy+(by)^2+(bx)^3-2abxy+(ay)^2
=(ax)^2+(by)^2+(bx)^2+(ay)^2
=(a^2+b^2)(x^2+y^2)