f(x)=1+sin(2x)+4(sinx+cosx) 求最小值f(x)=1+sin(2x)+4(sinx+cosx)求最小值答案是2-4√2

傅里叶级数作图f（x）=2sin[x] - sin[2x] + 2/3sin[3x] - 1/2sin[4x]我用mathematica输入程序Plot[{2sin[x],-2sin[x],2sin[x] - sin[2x],-2sin[x] + sin[2x],2sin[x] - sin[2x] + 2/3sin[3x],-2sin[x] + sin[2x] - 2/3sin[3x],2sin[x] - sin[2x] + 2/3si 已知函数f(x)=(1+1 anx)sin^2x+m sin(x+π/4)sin(x-π/4) f(x)=（1+cotx)sin^2x-2sin(x+π/4)sin(x-π/4)还有一题, f(x)=(6sin^4x-7sin^2x+2)/(sin^2x-cos^2x) 函数f(x)=负根号3sin ^2x+sin x cos x f(a/2)=1/4-根号3/2求sin a值 f(sin 2/x )=1+cosx 求f(x) 求导f(x) = 4x^3 + sin(x^2) 若f(x)=sin(π/4)x,求f(1)+f(2)+.+f(2010) 函数f(x)=2sin(x+π/4)sin(x-π/4)+sin2x的值域 求f【x】=2sin[x+π/4]sin[x-π/4]+sin2x的最大值 已知函数f(x)=-1/2+sin(5/2x)/2sin(x/2)(0 已知f(x)=cos^2x/1+sin^2x求f'(π/4)求导 已知函数f(x)=loga(1+sin^2(x/2)-sin^4(x/2)),其中0 s = 2*sin(x)-sin(2*x)+2/3*sin(3*x)-1/2*sin(4*x)+2/5*sin(5*x)用matlab画图,求教啊 证明一个sin&cos的等式证明 1+sin^2(x)+sin^4(x)+sin^6(x)=[1-sin^8(x)]/[cos^2(x)] F(X)=COS平方*x - sin平方*x + 根号3*SIN平方*x + 1 ,求F（X）的最大值和最小值及周期,F(X)=COS平方*x - sin平方*x + 根号3*SIN平方*2x + 1 我算到 F（X）=2SIN(X+1/4)+1 后面答案怎么求？ f(x)=(1+1/tanx)sin(x)^2化简 f(x)=sin^2x+sinxcosx-1/2,化简