x+y+z=18 x-2y=0 x+2y+5z=35 解二元一次
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x+y+z=18x-2y=0x+2y+5z=35解二元一次x+y+z=18x-2y=0x+2y+5z=35解二元一次x+y+z=18x-2y=0x+2y+5z=35解二元一次x+y+z=18x-2y=
x+y+z=18 x-2y=0 x+2y+5z=35 解二元一次
x+y+z=18 x-2y=0 x+2y+5z=35 解二元一次
x+y+z=18 x-2y=0 x+2y+5z=35 解二元一次
x+y+z=18 x-2y=0 x+2y+5z=35
x=2y
z=18-x-y=18-3y
2y+2y+5(18-3y)=35
-11y=-55
y=5
x=10
z=3
x=10 y=5 z=3
不好意思,这是三元一次
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