f(x)=ax^3+bx^2+cx f(x)在x=-1有极值曲线y=f(x)在(3,-24)处的切线方程为8x+y=0 求a,b,c
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/23 19:52:18
f(x)=ax^3+bx^2+cxf(x)在x=-1有极值曲线y=f(x)在(3,-24)处的切线方程为8x+y=0求a,b,cf(x)=ax^3+bx^2+cxf(x)在x=-1有极值曲线y=f(x
f(x)=ax^3+bx^2+cx f(x)在x=-1有极值曲线y=f(x)在(3,-24)处的切线方程为8x+y=0 求a,b,c
f(x)=ax^3+bx^2+cx f(x)在x=-1有极值曲线y=f(x)在(3,-24)处的切线方程为8x+y=0 求a,b,c
f(x)=ax^3+bx^2+cx f(x)在x=-1有极值曲线y=f(x)在(3,-24)处的切线方程为8x+y=0 求a,b,c
y'=3ax^2+2bx+c
将x=-1,y'=0代入得方程1 3a-2b+c=0
将x=3代入,得方程2 k=y'=27a+6b+c=-8
将x=3,y=-24代入得方程3 27a+9b+3c=-24
解这三个方程可得a,b,c
已知函数F(x)=ax^3+bx^2+cx(
已知f(x)=ax^5+bx^3-cx-6且f(-2)=8,求f(2)
设函数f(x)=1/3ax^3+bx^2+cx(a
f(x)=1/3ax^3+bx^2+cx(a
(2x-1)^5=ax^5+bx^4+cx^3+dx^2+ex+f
设三次函数f(x)=ax^3+bx^2+cx+d(a
设f(x)=ax^3+bx^2+cx+d,(a
设三次函数f(x)=ax^3+bx^2+cx+d(a
设f(x)=ax^3+bx^2+cx+d,(a
像f(x)=aX^3+bX^2+cX+d这种方程怎样化简呢
已知等式(x-3)*(x-3)*(x-3)*(x-3)*(x-3)*=ax*ax*ax*ax*ax*+bx*bx*bx*bx*+cx*cx*cx+dx*dx*+ex+f ,求a-b+c-d+e
若(3x+1)^5=ax^5+bx^4+cx^3+dx^2+ex+f,求f的值
已知0和1是函数f(x)=ax^3+bx^2+cx+d的零点,且f(-1)
若函数f(x)=ax^3+bx^2+cx+d满足f(0)=f(x1)=f(x2)=0,(0
f(x)=ax^7-bx^5+cx^3+2,且f(-5)=m,则f(5)+f(-5)的值为,
已知f(x)=ax^7-bx^5+cx^3+2,且f(-5)=m,则f(5)+f(-5)的值为?
已知f(x)=ax^7-bx^5+cx^3+2,且f(-5)=m,则f(5)+f(-5)的值为
已知f(x)=ax^5-bx^3+cx+2,且f(-5)=m,则f(5)+f(-5)的值为