证明loga^M^n=nloga^M

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证明loga^M^n=nloga^M证明loga^M^n=nloga^M证明loga^M^n=nloga^Mlog(a)[M]=K,则:M=a^KM^n=[a^k]^n=a^(Kn)则:log(a)[

证明loga^M^n=nloga^M
证明loga^M^n=nloga^M

证明loga^M^n=nloga^M
log(a)[M]=K,则:
M=a^K
M^n=[a^k]^n=a^(Kn)
则:log(a)[M^n]=Kn=nlog(a)[M]

http://zhidao.baidu.com/question/486766271.html?oldq=1
(我回答过一个,too simple, sometimes naive)