已知x>1,y>1,z>1,log(x)W=24,log(y)W=40,log(xyz)W=12求log(z)W
来源:学生作业帮助网 编辑:六六作业网 时间:2025/01/11 13:12:32
已知x>1,y>1,z>1,log(x)W=24,log(y)W=40,log(xyz)W=12求log(z)W已知x>1,y>1,z>1,log(x)W=24,log(y)W=40,log(xyz)
已知x>1,y>1,z>1,log(x)W=24,log(y)W=40,log(xyz)W=12求log(z)W
已知x>1,y>1,z>1,log(x)W=24,log(y)W=40,log(xyz)W=12求log(z)W
已知x>1,y>1,z>1,log(x)W=24,log(y)W=40,log(xyz)W=12求log(z)W
60
log(x)W=lgW/lgx = 24 lgx=lgW/24
log(y)W=40=lgW/lgy lgy=lgW/40
log(xyz)W=12=lgW/(lgx+lgy+lgz) so lgz= lgW/60
so log(z)W=60
用换底公式把底数与真数换位,再用减法,合并成真数除法,在换底倒会即可
log(x)W=24---log(W)x=1/24
log(y)W=40----log(W)y=1/40
log(xyz)W=12----log(W)xyz=1/12
log(W)z=log(W)xyz-log(W)x-log(W)y=1/60
log(z)W=60
已知x>1,y>1,z>1,log(x)W=24,log(y)W=40,log(xyz)W=12求log(z)W
已知x,y,z均大于1,w不等于0,log x w=24,log y w=40,log xyz w=12,求log z w
log(2x)+log(3y)-log(2z) 怎么化简?log3(x^2-2x-6)=2 log(3x+6)=1+log(x)求解,求每步详...log(2x)+log(3y)-log(2z) 怎么化简?log3(x^2-2x-6)=2 log(3x+6)=1+log(x)求解,
已知 x/(y+z)+y/(z+x)+z/(x+y)=1求 (x*x)/(y+z)+(y*y)/(x+z)+(z*z)/(x+y)=?
已知0<a<1,x=log a 根号2+log a 根号3y=1/2 log a 5z=log a 根号21 -log a 根号3比较x y z 的大小关系x=log a (根号2)+log a (根号3)y=1/2 (log a 5)z=log a (根号21) -log a (根号3)
matlab 极小化函数f(x,y) = -9*y - 10*z + 100*(-1*log(100-y-z)) - log(y) - log(z) - log(50-y+z)matlab怎么极小化这个函数,我搞的老是出错
log(2x)+log(3y)-log(2z) 怎么化简? log3(x^2-2x-6)=2 log(3x+6)=1+log(x)求解.
已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值
已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值
2log(m)y-log(m)x-log(m)z
已知x,y满足不等式组{x≥1 x+y-4≤0 x-y≤0,则z=log以1/2为底(2x+y)的对数的最大值为
已知实数X.Y.Z满足(Y+Z)分之X+(Z+X)分之Y+(X+Y)分之Z=1,则(Y+Z)分之X平方+(Z+X)分之Y平方+(X+Y)分之Z平方的值为( )
已知x,y,z>0,xyz(x+y+z)=1,求证(x+y)(x+z)>=2
3、已知x,y,z都是大于1的正数,m>0,且log(x)m=24,log(y)m=40,log(xyz)m=12,则log(z)m的值为A.B.60 C.D.A.1/60 B.60 C.200/3 D.3/20
一条分式数学题已知x y z满足x/x+y + y/z+x + z/x+y =1,求x²/x+y + y²/z+x + z²/x+y的值.3Q
已知x,y,z满足 -------------- + --------------- + ------------- = 1 y+z x+z x+yx•x y•y z•z求 ------------ + ------------ + -------------- = y+z x+z x+y
1、y-x/x²-y²2、(x-y)(y-z)(z-x)/(z-y)(y-x)(x-z)
帮忙解道题 ,已知x+1/y=y+1/z=z+1/x ,证明x+y+z=1