数据库group by语句select * from hb_student_info where card_id in(select card_id from hb_student_info group by card_id having count(card_id)>1)我知道这句的功能是查找出card_id相同的纪录 具体是怎么实现功能的,count函数

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/27 19:00:24
数据库groupby语句select*fromhb_student_infowherecard_idin(selectcard_idfromhb_student_infogroupbycard_idh

数据库group by语句select * from hb_student_info where card_id in(select card_id from hb_student_info group by card_id having count(card_id)>1)我知道这句的功能是查找出card_id相同的纪录 具体是怎么实现功能的,count函数
数据库group by语句
select * from hb_student_info where card_id in(select card_id from hb_student_info group by card_id having count(card_id)>1)
我知道这句的功能是查找出card_id相同的纪录 具体是怎么实现功能的,count函数大于1是什么意思?

数据库group by语句select * from hb_student_info where card_id in(select card_id from hb_student_info group by card_id having count(card_id)>1)我知道这句的功能是查找出card_id相同的纪录 具体是怎么实现功能的,count函数
select card_id from hb_student_info group by card_id having count(card_id)>1
group by 是按照card_id分组,配合having做条件筛选
比如hb_student_info中数据如下:
card_id 栏位1 栏位2
001 1 2
001 2 2
001 3 4
002 4 4
003 4 4
003 2 3
通过group by 分组后
card_id
001
002
003
此时在select 中加入count(card_id) 去看 select card_id,count(card_id)from hb_student_info group by card_id
card_id count(card_id)
001 3
002 1
003 2
通过这样的数据就可以看出 只有001和003是符合条件的(即card_id有相同的记录)
in 后面的查询条件就是通过筛选分组后card_id>1的数目找出所有的card_id

SQL语句select * from 表名 group by 列名--不是 GROUP BY 表达式RTselect * from 表名 group by 列名----- 报错 ORA-00979:不是 GROUP BY 表达式数据库:oracle10g* 换成 列名也不行 数据库group by语句select * from hb_student_info where card_id in(select card_id from hb_student_info group by card_id having count(card_id)>1)我知道这句的功能是查找出card_id相同的纪录 具体是怎么实现功能的,count函数 关于SQL语句里面的A.XX,和B.select B.kecheng,B.score,B.xuehaofrom(select kecheng ,max(score) AS score from jiaScore group by kecheng) A,jiaScore Bwhere A.kecheng = B.kechengand A.score = B.score例如我这段数据库语句,A.kecheng和B.keche 如何理解聚合函数通常与group by 子句一起使用,如果一个select 语句中有一个group by子句,则这个聚合函数对所有的列起作用,如果没有,则select语句只产生一个结果. mysql中的select语句where条件group by ,having ,order by,limit的顺序及用法写一个把他们都用上的例子 select-sql 语句中,筛选用(?)子句,分组用group by 子句,排序用order by 子句上述括号中筛选用什么子句? 数据库的group by有什么意义呢?(sql server) group by order by今天发现一个很有意思的问题,对于一个sql语句,其后的group by 1 order by 1 比如:select to_char(created_date,'%Y%m'),count(*)from aaaagroup by 1 order by 1 其中的created_date为日期格式,该语句想按月 SQL语句中的 Distinct 和 Group by 有什么不同,用那个好?select Distinct 品名,单位 from [表]和select 品名,单位 from [表]Group by 品名,单位查询的结果是一样的,都是把相同的记录合并为一条,这两个有什么 下面的SQL语句select * from [viwBasket] where tblUser=' + (string)Session[User] + 'order by ID desc其中的 [viwBasket]是什么意思,我的数据库里并没有这张表,为什么要加个中括号. SQL的执行顺序,如:( Select,From,Where Group By , Order By)如何的顺序 select a,b from 表名 group by a,b order by count(*) desc 在SQL语句中,select,where,group by,having,order by,这几个关键字程序执行顺序是怎样的?比如这个查询语句:select T1.USERNAME AS '员工姓名',T2.DEPTNAME as '部门名称',sum(T3.BILLMNY) AS '出账收入',sum(T4.LOSTMNY) AS order by 与group by 数据库高手看看我刚学数据库,也可以进数据库开发研究Q群13578732交流 group的语句能否写成where?where的语句能否写成group by? 如何提高下面语句的效率select * from(select a_month ,b_name ,count(DISTINCT a.c_no) ,dense_rank() over (partition by a_month order by COUNT( DISTINCT a.c_no) desc) rank fromsut_s aleft join cou_c bon a.ll=b.ll where a_month>='10'group by b_ select id from (select id from pedigree group by number having count(name)>1)as a; 为啥用as a 关于group by 语句要检索至少选修了一门课程的女生的姓名.(书上给出表格)要我们写select语句.答案是这样的 select snamefrom student ,scwhere sex='女'and student.sno= sc.snogroup bu snamehaving count(*)>=1我怎