英语Our teacher told us not to spend much time on playing.甲乙两地相距140KM,一船在两地间航行,顺流用了7h,逆流用了10h,则这艘船在静水中的速度是（ ）,水流速度是（ ）

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英语Ourteachertoldusnottospendmuchtimeonplaying.甲乙两地相距140KM,一船在两地间航行,顺流用了7h,逆流用了10h,则这艘船在静水中的速度是（）,水流速

英语Our teacher told us not to spend much time on playing.甲乙两地相距140KM,一船在两地间航行,顺流用了7h,逆流用了10h,则这艘船在静水中的速度是（ ）,水流速度是（ ）
英语Our teacher told us not to spend much time on playing.
甲乙两地相距140KM,一船在两地间航行,顺流用了7h,逆流用了10h,则这艘船在静水中的速度是（ ）,水流速度是（ ）

英语Our teacher told us not to spend much time on playing.甲乙两地相距140KM,一船在两地间航行,顺流用了7h,逆流用了10h,则这艘船在静水中的速度是（ ）,水流速度是（ ）
英语：We were told not to spend much time on playing by our teacher.
数学：设船在静水中的速度为v1,水的速度为v2
那么：140/（v1+v2)=7
140/ (v1-v2)=10
解方程组可得：v1=17km/h v2=3km/h
v1+v2为顺水速度；v1-v2为逆水速度

Our teacher told us not to spend much time on playing.
我想应该是翻译吧 或者是什么
如果是翻译就是
我们老师告诉我们叫我们不要花太多的时间去玩
++ 至于是别的问题 你可以再问

1。设水流速度a，船在静水的速度为v，则：140/（a+v）=7;140/(v-a)=10;解两个方程式得，v=17；a=3，即穿在静水中的速度为17km/h；水流速度为3km/h，
2。【（140/7）-（140/10）】/2=3；
顺水时船速（静水船速+水速）-逆水时船速（静水船速-水速）=2倍水速
老师让我们不要花太多的时间在玩上。...

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1。设水流速度a，船在静水的速度为v，则：140/（a+v）=7;140/(v-a)=10;解两个方程式得，v=17；a=3，即穿在静水中的速度为17km/h；水流速度为3km/h，
2。【（140/7）-（140/10）】/2=3；
顺水时船速（静水船速+水速）-逆水时船速（静水船速-水速）=2倍水速
老师让我们不要花太多的时间在玩上。

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