用因式分解法解(1+√2)x²－(1－√2)x＝0 急

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用因式分解法解(1+√2)x²－(1－√2)x＝0急用因式分解法解(1+√2)x²－(1－√2)x＝0急用因式分解法解(1+√2)x²－(1－√2)x＝0急(1+√2)x

用因式分解法解(1+√2)x²－(1－√2)x＝0 急
用因式分解法解(1+√2)x²－(1－√2)x＝0 急

(1+√2)x²-(1-√2)x=0
x[(1+√2)x-(1-√2)]=0
x1=0
x2=(1-√2)/(1+√2)
=(1-√2)²/[1-(√2)²]
=-1-2√2+2
=1-2√2