计算x-3/2x-4÷(5/(x-2)-x-2)
来源:学生作业帮助网 编辑:六六作业网 时间:2025/01/13 01:23:06
计算x-3/2x-4÷(5/(x-2)-x-2)计算x-3/2x-4÷(5/(x-2)-x-2)计算x-3/2x-4÷(5/(x-2)-x-2)[(x-3)/(2x-4)]÷[5/(x-2)-x-2]
计算x-3/2x-4÷(5/(x-2)-x-2)
计算x-3/2x-4÷(5/(x-2)-x-2)
计算x-3/2x-4÷(5/(x-2)-x-2)
[(x-3)/(2x-4)]÷[5/(x-2)-x-2]
=[(x-3)/(2x-4)]÷[5/(x-2)-(x+2)(x-2)/(x-2)]
=[(x-3)/(2x-4)]÷[(5-x²+4)/(x-2)]
=(x-3)/(2x-4)×(x-2)/(9-x²)
=(x-3)/(2x-4)×(x-2)/[(3-x)(3+x)]
= -1/(6+2x)
计算(x*x+4x+5)/(x+2)-(x*x+6x+10)/(x+3)+1
计算x-3/2x-4÷(5/(x-2)-x-2)
x^2-1/x^2+4x+4÷(x+1)×x^2+3x+2/x-1计算
计算 2x-6/x²-4x+4 ÷(x+3)×x²+x-6/3-x
计算:[x(-4X+3)+(X-2)x]÷(-X)
计算:5x²-[3x-(4x-3x)-2x²]
x/x-3-5x/x^2-x-6计算
计算:x/x-2 - 5x/x²-x-6计算:x/x-3 - 5x/x²-x-6
2x*4x-3x计算
【计算(过程)】-x^2*(-x)^3+3x^3*(-x^2)-4(-x)*(-x)^4
计算:(x-1)(x^2-4X+3)-x(x^2-5X+2)有过程
计算:(2x+3)(3x-4)>(x+1)(x-1)+5x(x+3)+7
计算:[(x+2)/(x+3) - (x+1)/(x+2) + (x+4)/(x+5) - (x+3)/(x+4) / (x^2 + 7x + 13)/(x^2 + 8x + 15)
分式计算 (x+2/x-2+4/x平方-4x+4)÷x/x-2*x-2/x
如何计算(x-1)(x-2)(x-3)(x-4)-(x^2-5x)^2-10(x^2-5x)
用简便方法计算 (x-2)(x-3)+(x-4)(x-5)+(x-2)(x-4)+(x-3)(x-5)
计算(x+2)/(x+1) - (x+3)/(x+2) + (x+4)/(x+3) - (x+5)/(x+4)
分式计算:x^5-4x^3+x+2/x^3+6x^2+12x+8(约分)RT