1.(1-x)/(x-2)=[1/(2-x)]-22.[(x-3)/(x²-1)]-[2/(1+x)]
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1.(1-x)/(x-2)=[1/(2-x)]-22.[(x-3)/(x²-1)]-[2/(1+x)]1.(1-x)/(x-2)=[1/(2-x)]-22.[(x-3)/(x²-1
1.(1-x)/(x-2)=[1/(2-x)]-22.[(x-3)/(x²-1)]-[2/(1+x)]
1.(1-x)/(x-2)=[1/(2-x)]-2
2.[(x-3)/(x²-1)]-[2/(1+x)]
1.(1-x)/(x-2)=[1/(2-x)]-22.[(x-3)/(x²-1)]-[2/(1+x)]
(1-x)/(x-2)=(2x-3)/(2-x)
2-3x+x^2=2x^2-7x+6
x^2-4x+4=0
(x-2)^2=0
x=2
检验:因为等式右边含有1/(2-x),x≠2
所以没解
原式=[(x-3)-2(x-1)]/(x^2-1)
=-(x+1)/(x^2-1)
=1/(1-x)
计算:(1+1/x)·x²-2x+1/x²-1;(x²/x-1-2x/1-x)÷x/x-1.
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