计算:[(4x^2-1/2y)^2+4y(x^2-1/16y)]÷(-8x^2)
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/23 04:11:37
计算:[(4x^2-1/2y)^2+4y(x^2-1/16y)]÷(-8x^2)计算:[(4x^2-1/2y)^2+4y(x^2-1/16y)]÷(-8x^2)计算:[(4x^2-1/2y)^2+4y
计算:[(4x^2-1/2y)^2+4y(x^2-1/16y)]÷(-8x^2)
计算:[(4x^2-1/2y)^2+4y(x^2-1/16y)]÷(-8x^2)
计算:[(4x^2-1/2y)^2+4y(x^2-1/16y)]÷(-8x^2)
[(4x^2-1/2y)^2+4y(x^2-1/16y)]÷(-8x^2)
=[16x^4-4x^2y+1/4y^2+4yx^2-1/4y^2)]÷(-8x^2)
=16x^4÷(-8x^2)
=-2x²
如追加其它问题,
计算:2xy/(x+y)².(x+y)/4y
计算:(4xy(x-y)^-1+(x(y^-1)-(x^-1)y)/((x^-1)+(y^-1)))*(x+y)^-2
计算:(x-2y)(x+y)-2y(1-4y)=
计算:1/(x-y)-1/(x+y)-2y/(x^2+y^2)-4y^3/(x^4+y^4)-8x^7/(x^8+y^8)
计算(2x-3y)(x+4y)-(3x+y)(x-2y)(2x-3y)(x+4y)-(3x+y)(x-2y)
(x-3y)(y+2x)-(4y-3x)(3x+4y)计算
计算:(x-y)^2*(x+y)^3*(-x-y)^3*(y-x)^4
计算:[(x+y)³-2(x+y)²-4(x+y)]÷(x+y)
计算[(x+y)的立方-2(x+y)的平方-4(x+y)]÷(-x-y)
计算:(x-2y)(1+x+2y+4y^2+2xy+x^2)
计算1-(x-2y/x+2y)/(x^2-y^2/4xy-x^2-4y^2)
计算:[(2x - 3y)^2 - (x-y)(4x+2y)] / 2y
计算:[1/(x-y) - 1/(x+y) + 2y/(x^2 + y^2) - 4x^2 y/(x^4 + y^4)
计算 (x^8+y^8)(x^4+y^4)(x^2+y^2)(x+y)(x-y)
分式计算(x-y-4y^2/x-y)(x+y-4x^2/x+y)=?
如何计算4x*4y-2x*2y
(x-2y+4)(x-2y-4) 计算
计算(4x^2-y^2)/(2x+y)=