若(2x-3y+5)^2+|x+y-2|=0,则x= y=
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若(2x-3y+5)^2+|x+y-2|=0,则x=y=若(2x-3y+5)^2+|x+y-2|=0,则x=y=若(2x-3y+5)^2+|x+y-2|=0,则x=y=平方和绝对值大于等于0,相加等于
若(2x-3y+5)^2+|x+y-2|=0,则x= y=
若(2x-3y+5)^2+|x+y-2|=0,则x= y=
若(2x-3y+5)^2+|x+y-2|=0,则x= y=
平方和绝对值大于等于0,相加等于0,若有一个大于0,则另一个小于0,不成立.
所以两个都等于0
所以2x-3y+5=0
x+y-2=0
解方程组
x=1/5,y=9/5
(2x-3y+5)^2+|x+y-2|=0
2x-3y+5=0
x+y-2=0
x=1/5 y=9/5
(2x-3y+5)^2+|x+y-2|=0,则
2x-3y+5=0
x+y-2=0
联立方程,解得
x=11,y=-9
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