4a^2=( )^2 16/25X^4Y^2=( )^2 36(X+2Y)^2=[ ]^2 49(X-3Y)^2=[ ]^2 因式分解,
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4a^2=()^216/25X^4Y^2=()^236(X+2Y)^2=[]^249(X-3Y)^2=[]^2因式分解,4a^2=()^216/25X^4Y^2=()^236(X+2Y)^2=[]^2
4a^2=( )^2 16/25X^4Y^2=( )^2 36(X+2Y)^2=[ ]^2 49(X-3Y)^2=[ ]^2 因式分解,
4a^2=( )^2 16/25X^4Y^2=( )^2 36(X+2Y)^2=[ ]^2 49(X-3Y)^2=[ ]^2 因式分解,
4a^2=( )^2 16/25X^4Y^2=( )^2 36(X+2Y)^2=[ ]^2 49(X-3Y)^2=[ ]^2 因式分解,
4a^2=( 2a)^2
16/25X^4Y^2=(4/5x^2y )^2
36(X+2Y)^2=[6x+12y ]^2
49(X-3Y)^2=[7x=21y ]^2
4a^2=(2a )^2
16/25X^4Y^2=(4/5x^2y)^2
36(X+2Y)^2=[6(x+2y) ]^2
49(X-3Y)^2=[ 7(x-3y)]^2
4a^2=(±2a)^2
16/25X^4Y^2=(±4/5X^2Y)^2
36(X+2Y)^2=[±6(X+2Y)]^2
49(X-3Y)^2=[±7(X-3Y)]^2
因式分解-5a^2+25a;25x^2-16y^2;x^3-25x;x^2(x-y)+y^2(y-x);x^2y^4-16x^2;(a+b)^2+2(a+b)+1
25(x+y)^2+16(x-y)^2=4y(y-x)^2-6y(x-y)^3=(a-2b)^2+(a-2b)+1/4=
a(x+y)^2+4a-4a(x+y)
1(x-3x-1)(x+3y-1)2(3x-2y+1/4)²3(a+b)²-(a-b)²4 [2x²-(x+y)(x-y)][(-x-y)×(y-x)+2y²],其中x=1 y=25[(0.5x-y)²+(0.5x+y)²](0.5x²-2y²)6(a+3b)²-2(a+3b)(a-3b)+(a-3b)²7
(4x*4y-y-x-2x*2y)*a=?
-4a^3+16a^2b-26ab^2 x^5-x^3 (x^2+y^2)^2-4x^2y^2 25(x+y)^2+10(x+y)+1 a*(-a^2)^3*(a^3)^2
(2x+y)(2x-3y)+x(2y+y) 2a(x-y)-4b(x-y)
4a(x-y)二次方-2b(y-x)二次方+(y-x)=
-4(x+y)^2+4a(x+y)-a^2
已知集合A={(x,y)| (y-3)/ (x-1)=2,x,y∈R},B={(x,y)| 4x+ay=16,x,y∈ R},若A∩B=空集,则实数a=?
已知集合A={(x,y)| (y-3)/ (x-1)=2,x,y∈R},B={(x,y)| 4x+ay=16,x,y∈ R},若A∩B=空集,则实数a=?
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如果A={(x,y)|x,y+2>0},B={(x,y)|2x+3y-6>0},C={(x,y)|x-4