设f(x)=(ax+b)sinx+(cx+d)cosx 试确定abcd的值,使f'(x)=xsinx-cosx 答案是c=1 b=-2 a=d=0而我是 c=-1 b=2 a=d=0

设f(x)=(ax+b)sinx+(cx+d)cosx,若已知f'(x)=xcosx,则f(x)= 设f(x)=(ax+b)sinx+(cx+b)cosx,选择适当的常数a,b,c,d,使f'(x)=xcosx 设f(x)=(ax+b)sinx+(cx+d)cosx,求常数a b c d使得f(x)=xcosx f(x)=(ax+b)sinx+(cx+d)cosx,确定a,b,c,d,使f(x)求导=xcosx f(x)=(ax+b)sinx+(cx+d)cosx试确定常数a,b,c,d使得f`(x)=xcosf`(x)就是函数f(x)的导数 求f(x)=(ax+b)/(cx+d) 的反函数 已知f（x）=（ax+b）sinx+（cx+d）cosx,试,确定a,b,c,d使f’（x）=xcosx? f(x)=ax+b/cx+d的反函数怎么算?f(x)=(ax+b)/(cx+d) 设y=f(x)=ax+b/cx-a,证明x=f(y),其中a,b,c为常数,且a^2+bc不等于0 设f(x)=ax^5+bx^3+cx-5(a、b、c是常数),且f(-7)=7,则,f(7)= 设函数f(x)=ax^5+bx^3+cx,其中a,b,c为常数.若f(-7)=7,则f(7)的值为多少 设三次函数f(x)=ax^3+bx^2+cx+d(a 设f(x)=ax^3+bx^2+cx+d,(a 设函数f(x)=1/3ax^3+bx^2+cx(a 设三次函数f(x)=ax^3+bx^2+cx+d(a 设f(x)=ax^3+bx^2+cx+d,(a 设函数f(x)=1/3*ax;+bx;+cx(a 设（x-1)^5=ax^5+bx^4+cx^3+dx^2+ex+f,则a-b+c-d+e-f=?