设f(x)=ax^5+bx^3+cx-5(a、b、c是常数),且f(-7)=7,则,f(7)=

设f(x)=ax^5+bx^3+cx-5(a、b、c是常数),且f(-7)=7,则,f(7)= 设f（x）=ax^5+bx^3+cx+2,若f（-3）=28,则f（3）等于多少? 设f(x)=ax^7+bx^3+cx-5,其中abc为常数,已知f(-7)=7,则f(7)等于 设函数f(x)=ax^5+bx^3+cx,其中a,b,c为常数.若f(-7)=7,则f(7)的值为多少 设5不整除d,f(x)=ax^3+bx^2+cx+d,g(x)=dx^3+cx^2+bx+a,证明：若存在m,使得5|f(m),则存在n使得5|g(n) 设函数f(x)=1/3ax^3+bx^2+cx(a 设三次函数f(x)=ax^3+bx^2+cx+d(a 设f(x)=ax^3+bx^2+cx+d,(a 设三次函数f(x)=ax^3+bx^2+cx+d(a 设f(x)=ax^3+bx^2+cx+d,(a 设函数f(x)=1/3*ax;+bx;+cx(a 设（x-1)^5=ax^5+bx^4+cx^3+dx^2+ex+f,则a-b+c-d+e-f=? (2x-1)^5=ax^5+bx^4+cx^3+dx^2+ex+f 已知 f(x)=x^5+2x-x+3,且f(2)=7,求f(-2).还有,设函数f(x)=ax^5=bx^3+cx,若f(2)=15,则f(-2)=? 已知函数F(x)=ax^3+bx^2+cx( 设(2x-1)^5=ax^5+bx^4+cx^3+dx^2+ex+f求a+c+e的值 已知函数f(x)=ax^5+bx^3+cx+3,若f(5)=8,求f(-5) f(x)=ax{5次方}+bx{3次方｝＋cx+5,且f(-3)=3,求f(3)