若x^2+y^2+2x-2y+2=0则x+y=?
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若x^2+y^2+2x-2y+2=0则x+y=?若x^2+y^2+2x-2y+2=0则x+y=?若x^2+y^2+2x-2y+2=0则x+y=?x^2+y^2+2x-2y+2=0(x+1)^2+(y-
若x^2+y^2+2x-2y+2=0则x+y=?
若x^2+y^2+2x-2y+2=0则x+y=?
若x^2+y^2+2x-2y+2=0则x+y=?
x^2+y^2+2x-2y+2=0
(x+1)^2+(y-1)^2=0
x+1=0,y-1=0
x=-1,y=1
x+y=0
x^2+y^2+2x-2y+2=0
(x²+2x+1)+(y²-2y+1)=0
(x+1)²+(y-1)²=0
x+1=0, y-1=0
x=-1,y=1
x+y=0
x^2+y^2+2x-2y+2=0
(x^2+2x+1)+(y^2-2y+1)=0
(x+1)^2+(y-1)^2=0
x=-1
y=1
x+Y=-1+1=0
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
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