(lim→-1)sin(x+1)/2(x+1)
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(lim→-1)sin(x+1)/2(x+1)(lim→-1)sin(x+1)/2(x+1)(lim→-1)sin(x+1)/2(x+1)令a=x+1则a→0所以原式=lim(a→0)sina/a*1
(lim→-1)sin(x+1)/2(x+1)
(lim→-1)sin(x+1)/2(x+1)
(lim→-1)sin(x+1)/2(x+1)
令a=x+1
则a→0
所以原式=lim(a→0)sina/a*1/2
=1*1/2
=1/2
(lim→-1)sin(x+1)/2(x+1)
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