[(-3ab)²×a³+2a³×(-3ab)³×1/2b]÷(3a²b²)² ,其中a=1/3,b=-b=-(1/2)
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/23 03:26:36
[(-3ab)²×a³+2a³×(-3ab)³×1/2b]÷(3a²b²)²,其中a=1/3,b=-b=-(1/2)[(-3ab)
[(-3ab)²×a³+2a³×(-3ab)³×1/2b]÷(3a²b²)² ,其中a=1/3,b=-b=-(1/2)
[(-3ab)²×a³+2a³×(-3ab)³×1/2b]÷(3a²b²)² ,其中a=1/3,b=-
b=-(1/2)
[(-3ab)²×a³+2a³×(-3ab)³×1/2b]÷(3a²b²)² ,其中a=1/3,b=-b=-(1/2)
[(-3ab)²×a³+2a³×(-3ab)³×1/2b]÷(3a²b²)²
=[-3a^5b^2-3a^6b^2]÷9a^4b^4
=-a/3b^2-a^2/3b^2
=-a/3b^2*(a-1)
=-a/3b^2*0
=0