① (x-5)/8+40=(x-5)/6② x+(3x+1)+(x/2 -1)=180

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①(x-5)/8+40=(x-5)/6②x+(3x+1)+(x/2-1)=180①(x-5)/8+40=(x-5)/6②x+(3x+1)+(x/2-1)=180①(x-5)/8+40=(x-5)/6②

① (x-5)/8+40=(x-5)/6② x+(3x+1)+(x/2 -1)=180
① (x-5)/8+40=(x-5)/6
② x+(3x+1)+(x/2 -1)=180

① (x-5)/8+40=(x-5)/6② x+(3x+1)+(x/2 -1)=180
1.两边通分,同乘以48,得
6(x-5)+40*48=8(x-5)
2(x-5)=40*48
x-5=960,所以x=965
2.归纳同类项,得4x+x/2=180,两边同乘以2,得:8x+x=360,x=40

(x-5)/8+40=(x-5)/6
=>(x-5)/6-(x-5)/8=40
=>(x-5)/24=40
=>x-5=960
=>x=965
x+(3x+1)+(x/2-1)=180
=>2x+6x+x+2-2=360
=>9x=360
=>x=40