$id="select id from account where name='".$_SESSION['login']."'";if($_GET["tj"]=="modify") {if($_POST["submit"]){\x05mysql_query($sql="update user set level='".$_POST['level']."' where account_id='".$id."'");\x05echo "alert('修改成功');location='

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/23 18:04:26
$id="selectidfromaccountwherename=''".$_SESSION[''login'']."''";if($_GET["tj"]=="modify"){if($_POST["sub

$id="select id from account where name='".$_SESSION['login']."'";if($_GET["tj"]=="modify") {if($_POST["submit"]){\x05mysql_query($sql="update user set level='".$_POST['level']."' where account_id='".$id."'");\x05echo "alert('修改成功');location='
$id="select id from account where name='".$_SESSION['login']."'";
if($_GET["tj"]=="modify") {
if($_POST["submit"]){
\x05mysql_query($sql="update user set level='".$_POST['level']."' where account_id='".$id."'");
\x05echo "alert('修改成功');location='login.php';";
1、一共两个表 account和user 两个表里唯一互通的是ID.name都不同,但我想把A表ID定义出来让U表判断ID然后提升会员等级
2、我要如何把 account表里的id给定义出来呢,$_session['login']里定义的是name

$id="select id from account where name='".$_SESSION['login']."'";if($_GET["tj"]=="modify") {if($_POST["submit"]){\x05mysql_query($sql="update user set level='".$_POST['level']."' where account_id='".$id."'");\x05echo "alert('修改成功');location='
$id="select id from account where name='".$_SESSION['login']."' LIMIT 1";
$sql=mysql_query($id);
$res=mysql_fetch_assoc($sql);
.
mysql_query($sql="update user set level='".$_POST['level']."' where account_id='".$sql['id']."'");

$query = mysql_query( select * from 表名 where id='$_GET[id]' )中'$_GET[id]'是什么意思? select id,name from student where id in ( select id from score having count(id)>=2 );以上这段语句有没语法错误.SQL语句 请问sql=select * from 招聘信息 order by id sql语句:去掉最大值,去掉最小值,算平均值SELECT AVG(Scores.Score)FROM ScoresWHERE ( ( (Scores.[ID]) = @id)AND (Score < (SELECT MAX(Score) From Scores WHERE Scores.[ID] = @id) )AND (Score > (SELECT MIN(Score) From Scores WHERE Scores.[I 请教sql语句,像select …from wsdy_zb t where t.id =:id order by no desc 中t.id =:id 为什么 select * from student left outer join takes on true where student.id=takes.id; 运行不了为什么 select * from student left outer join takes on true where student.id=takes.id; 运行不了 这是书上的 谁能帮我挑挑错?mycmd.CommandText = select id from & m1_TableName & where id=' & ddlid.SelectedItem.Text & ' nsql=select * from gonggao where passed=1 order by id desc SQL语句理解 select * from B where (select count(1) as num from A where A.ID = B.ID) = 0select * from B where (select count(1) as num from A where A.ID = B.ID) = 0请问如何理解,为什么 可以在B表中 排除A表的数据 sql中left join from 多个表怎么写select * from a,b,c,d LEFT JOIN e on e.id=a.id left join f on f.id=c.id现在这句是错的,怎么写才正确 select Field_Content,ID*1 as ID,[index]=identity(int,1,1) into #temp from user_Pro where categoryid= + id+ order by indexid desc; select * from #temp; drop table #temp; select Field_Content,ID*1 as ID,[index]=identity(int,1,1) into #temp from user_Pro where categoryid= + id+ order by indexid desc; select * from #temp; drop table #temp; select id from (select id from pedigree group by number having count(name)>1)as a; 为啥用as a select top 1 ID from Net_dictionary,其中top1 ID指的是什么? 英语翻译update table set ID=left(ID,charindex('-',ID)-1)+'-'+right(('00000'+right(ID,len(_ID)-charindex('-',ID))),9)from table where len(ID)-charindex('-',ID)9 sql如何取交集有这样两条sql语句select distinct id from a where id='123'select distinct id from a where id='456'我希望能把他们取得他们记录的交集,sql语句该如何写?错了 应该是这样的select distinct temid from a whe sql = Select * from product_series order by index desc,id asc 我想写查询id小于等于7的序列,怎么改 大量的left join 怎么优化select a.id,a.num,b.num,b.pcs,c.num,c.pcs,d.num,d.pcs,e.num,e.pcs,a.x,a.y from a left join b.id=a.id and b.time=a.timeleft join c.id=a.id and b.time=a.timeleft join d.id=a.id and b.time=a.timeleft join e.id=a.id and b.t