lim n→无穷（6n-1）/（3n+1）=?

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limn→无穷（6n-1）/（3n+1）=?limn→无穷（6n-1）/（3n+1）=?limn→无穷（6n-1）/（3n+1）=?分子分母同除以n,得lim(6n-1)/(3n+1)=lim(6-1

lim n→无穷（6n-1）/（3n+1）=?
lim n→无穷（6n-1）/（3n+1）=?

lim n→无穷（6n-1）/（3n+1）=?
分子分母同除以n,得 lim (6n-1)/(3n+1) = lim (6-1/n)/(3+1/n) = 2

罗比达法则吧。。6/3

lim n→无穷（6n-1）/（3n+1）
=lim n→无穷（6-1/n）/（3+1/n）分子分母都除以n
=6/3
=2

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lim n→无穷 （6n-1）/（3n+1）=?