4[x+3]^2-3[x^2-8x+16]=0因式分解法怎么解?

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4[x+3]^2-3[x^2-8x+16]=0因式分解法怎么解?4[x+3]^2-3[x^2-8x+16]=0因式分解法怎么解?4[x+3]^2-3[x^2-8x+16]=0因式分解法怎么解?4[x+

4[x+3]^2-3[x^2-8x+16]=0因式分解法怎么解?
4[x+3]^2-3[x^2-8x+16]=0因式分解法怎么解?

4[x+3]^2-3[x^2-8x+16]=0因式分解法怎么解?
4[x+3]^2-3[x^2-8x+16]=0
4(x+3)²-3(x-4)²=0
(2x+6+√3x-4√3)(2x+6-√3x+4√3)=0
x=(-6+4√3)/(2+√3)=14√3-24
x=-14√3-24

4[x+3]^2-3[x-4]^2=0 因为:1 -4
1 -4 所以为:[x-4]^2

原式=4(x+3)^2-3(x-4)^2
=[2(x+3)-√3(x-4)][2(x+3)+√3(x-4)]
=[(2-√3)x+6+4√3][(2+√3)+6-4√3]=0
得,x=24±14√3

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