(1)1/2(2x-1)+1/3(2x-1)=5/6怎么解 (2)x-2x+3x-4x+...+99x-100x=25

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(1)1/2(2x-1)+1/3(2x-1)=5/6怎么解(2)x-2x+3x-4x+...+99x-100x=25(1)1/2(2x-1)+1/3(2x-1)=5/6怎么解(2)x-2x+3x-4x

(1)1/2(2x-1)+1/3(2x-1)=5/6怎么解 (2)x-2x+3x-4x+...+99x-100x=25
(1)1/2(2x-1)+1/3(2x-1)=5/6怎么解 (2)x-2x+3x-4x+...+99x-100x=25

(1)1/2(2x-1)+1/3(2x-1)=5/6怎么解 (2)x-2x+3x-4x+...+99x-100x=25
(1)
原式=(1/2+1/3)(2x-1)
=5/6(2x-1)
=5/6.
所以2x-1=1,解得x=1.
(2)原式=(x-2x)+(3x-4x)+...+(99x-100x)
=-50x
=25,
所以x=-0.5

先两边同时乘以6 则可化为3(2x-1)+2(2x-1)=5
然后合并同类项 则可化为5(2x-1)=5 即可得出x=1
(2)原式可化为x(1-2+3-4+5........-100)=25
1-2=-1 3-4=-1 5-6=-1..........这样的一共有50组 即-50
所以原式为 -50x=25 即x=-1/2

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